00:01
Here, the free body diagram of block 1 is as follows.
00:10
Here, this is block 1 with mass m1.
00:14
There will be m1 into a acceleration because the elevator is moving downwards.
00:20
There will be normal reaction on block 1 due to block 2 because block 1 is resting on block 2.
00:27
Similarly, the weight of block that is m1 g factor acting downwards.
00:34
So here, the net force on block 1, which is f1, will be equal to m1 into a.
00:42
Here, m1 is 8 kilogram into the acceleration is 8 meter per second square.
00:49
Upon solving it turns out to be 64 newton and the vector form of the force f1 will be equal to here in the x direction there is 0 newton.
01:02
So 0 newton i cap minus here in the y direction we have 64 newton so 64 newton which is acting downwards so negative 64 newton j cap so this is the vector form now the weight of block 1 is given by the equation is w1 is equal to mass of block 1 into acceleration due to gravity which is equal to 8 kilogram into 9 .8 meter per second square and this turns out to be 78 .4 newton and the vector form of the weight is given by w1 is equal to 0 newton i cap minus 78 .4 newton j cap.
01:54
Therefore, here net force on block 1 is given by here the net force f1 is equal to the normal reaction on block 1 due to block 2 minus the m1 into g which is the weight of block.
02:16
Or we can say that here normal reaction on block 1 due to block 2 will be equal to force of block 1 plus the weight w1.
02:28
Upon substituting the values here, force on block 1 is 0 newton i cap minus 64 newton j cap plus here the weight is, which is m1 into g is 0 newton i cap minus 78 .4 newton j cap.
02:51
Upon solving we will get a normal reaction on block 1 due to block 2 is equal to 0 newton.
02:59
I cap minus 142 .4 newton j cap.
03:06
So this is the value.
03:08
This is j cap.
03:11
Now we need to do the free body diagram of block 2.
03:18
So the free body diagram of block 2 will be as follows...