Three capacitors are connected in combinations of series and parallel as shown. Determine (a) the equivalent capacitance of the circuit, (b) voltage across each capacitor, (c) the charge on each capacitor. 20 pts C\textsubscript{2} || 6\mu F C\textsubscript{1} 3\mu F C\textsubscript{3} 9\mu F + 50V
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The 6p4 F and 3p F capacitors are in parallel, and their equivalent capacitance is: C_parallel = C1 + C2 = 6.4 pF + 3 pF = 9.4 pF The 9pF capacitor is in series with the parallel combination, so the total capacitance of the circuit is: C_total = 1 / Show more…
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