00:01
Hi, there are three capacitors in this given problem which are, first of all, joined in a series combination and attached with a battery, providing 36 volt.
00:23
These capacitors are having capacitance of 8 .4 micro -farrid, 8 .4 micro -farrid, and 4 .2 .2 micro -farrid, and 4 .2.
00:34
To micro ferret.
00:36
Now, in the first part of the problem we have to find the charge on each of them as charge remains same in series.
00:57
So first of all, we find net capacitance, equivalent capacitance in series combination and that will be given by 1 by c equivalent is equal to 1 by 8 .4 plus 1 by 8 .4 plus 1 by 4.
01:14
2 .2 and that is 8 .4 lcm 1 plus 1 plus 2 means this is 4 by 8 .4 so equivalent capacitance is 8 .4 by 4 means this is 2 .1 micro -farrid now in this first part of the problem charge on each capacitor q that will be given by c equivalent multiplied by v.
01:48
So this is 2 .1 micro ferret multiplied by 36 volt.
01:55
So the charge in this series combination and charge over each capacitor comes out to be 75 .6 microculum which is the answer for the first part of the problem here...