00:01
Hi, everybody.
00:01
So we didn't find what is the charge on 4 .2 of the capsiter.
00:06
So we have a is going to be 1 over c1, which is 1c1 plus c2 plus c3.
00:23
Okay.
00:25
And this one, we're going to get 1 8 .4 plus 1 8 .4 plus 1 8 .4.
00:32
4 plus 1 4 .2.
00:40
Okay.
00:42
And this one, you get 22 .1 mu f.
00:47
And now the q is going to be 2 .1 times 36 volts, which is going to equal 75 .6 mu.
01:03
And that is your answer for that.
01:09
Okay.
01:11
And b is asking about, b wants to know what is the total energy stored in all three capsitters.
01:24
So we have one, two, three.
01:26
Okay.
01:28
So for this energy here, we can do q squared, okay? q squared divided by 2.
01:43
And this would be 1 over c1 plus 1 over c2 plus 1 over c3.
01:56
Okay.
01:58
And when we do this, we have 75 .6 u .c squared divided by 2 times times 1 over 8 .4 plus 1 over 8 .4 plus 1 4 .2.
02:20
Okay.
02:22
And we're just going to scroll down or attempt to scroll down.
02:28
There we go.
02:30
Okay.
02:31
And when we do that, we have, make the equal sign a little nicer...