Question

1. Three charges are arranged as shown. a. The magnitude of the electric field at point P due to one of the +Q charges is E?. What is the magnitude of the net electric field at P? Write answer in terms of E? and/or ? only. b. The electric potential at point P due to one of the +Q charges is V?. What is the net voltage at point P? Take V = 0 at infinity. Write answer in terms of V? and/or ? only. 2. Three charges are on a line as shown. An electron (charge -e, mass m) is released from rest at point A. We want to determine how fast the electron is moving at point B. a. A common mistake is to calculate the electric force on the electron at point A and then use Newton's 2?? law and constant acceleration kinematics to find the speed of the electron at point B. Why won't this work? b. Use conservation of energy to determine the speed of the electron a point B.

          1. Three charges are arranged as shown.
a. The magnitude of the electric field at point P due to one of the +Q charges is E?. What is the magnitude of the net electric field at P? Write answer in terms of E? and/or ? only.
b. The electric potential at point P due to one of the +Q charges is V?. What is the net voltage at point P? Take V = 0 at infinity. Write answer in terms of V? and/or ? only.
2. Three charges are on a line as shown. An electron (charge -e, mass m) is released from rest at point A. We want to determine how fast the electron is moving at point B.
a. A common mistake is to calculate the electric force on the electron at point A and then use Newton's 2?? law and constant acceleration kinematics to find the speed of the electron at point B. Why won't this work?
b. Use conservation of energy to determine the speed of the electron a point B.

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1. Three charges are arranged as shown.
a. The magnitude of the electric field at point P due to one of the +Q charges is E?. What is the magnitude of the net electric field at P? Write answer in terms of E? and/or ? only.
b. The electric potential at point P due to one of the +Q charges is V?. What is the net voltage at point P? Take V = 0 at infinity. Write answer in terms of V? and/or ? only.
2. Three charges are on a line as shown. An electron (charge -e, mass m) is released from rest at point A. We want to determine how fast the electron is moving at point B.
a. A common mistake is to calculate the electric force on the electron at point A and then use Newton's 2?? law and constant acceleration kinematics to find the speed of the electron at point B. Why won't this work?
b. Use conservation of energy to determine the speed of the electron a point B.

Added by Jose Ignacio G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

07/13/2023

Step 1

First, we need to find the electric field at point P due to each charge. The electric field due to one of the +Q charges is given as Eo. Since the charges are symmetrically placed, the electric field due to the other +Q charge at point P will also be Eo. The Show more…

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Three charges are arranged as shown. The magnitude of the electric field at point P due to one of the +Q charges is E₀. What is the magnitude of the net electric field at P? Write answer in terms of E₀ and/or Θ only. The electric potential at point P due to one of the +Q charges is V₀. What is the net voltage at point P? Take V = 0 at infinity. Write answer in terms of V₀ and/or Θ only. Three charges are on a line as shown. An electron (charge -e, mass m) is released from rest at point A. We want to determine how fast the electron is moving at point B. A common mistake is to calculate the electric force on the electron at point A and then use Newton's 2nd law and constant acceleration kinematics to find the speed of the electron at point B. Why won't this work? Use conservation of energy to determine the speed of the electron a point B.

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Transcript

00:01 Hello everybody, this problem is pretty interesting because here at point p the electric field is e0 for plus q charge so it will be plus q by l square into k.

00:17 So e0 value is this one.

00:19 So whatever we express we should express it as e0.

00:26 Now for this force, for this charge the force will be acting along ps direction because it will be repulsive force and here for this charge this force will be acting in pr direction.

00:39 This will also be repulsive force.

00:41 So the resultant of pr and ps will be equal to, we can find out e prime and that will be equal to e0 square plus e0 square plus 2 e0 square into cos 2 theta because this angle is given as theta and this is also theta.

01:13 So the whole angle between them will be 2 theta.

01:19 So from here this will be under root, so from here we get root 2 e0 into root 2 1 plus cos 2 theta and that will be equal to 2 e0 cos theta.

01:34 So we have got the value of the resultant between pr and ps.

01:39 Now for this charge minus 3q there will be an electric field here also acting and that will be attractive means towards this direction it will be acting.

01:51 Now this e prime also will be acting in this direction so the electric field for minus 3q will be added up to this e prime to get the resultant electric field or net electric field.

02:06 So for minus 3q charge the electric field at p is say this is we are going to find out say this is e...

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