00:01
In this problem, we have been given the three charges, q1, q2, and q3.
00:07
And the values of these charges are given here, and the separation is as mentioned, and we are required to determine the magnitude as well as the direction of the total force that this q1 charge experiences.
00:22
So first we observe that q1 charge that will experience an attractive force because of this charge, q2 and that will be towards the left direction and let's take the right direction as the positive x direction and the upward direction as the positive y direction so this force let's say it is f2 to determine the magnitude of f2 we use this column slot according to that the force is k k times q1 q2 by r square so magnitude of this force f2 that will be nine times 10 raised to 9 times the product of these two charges q1 and q2, which is 1 .2 times 4 .5 times 10 raised to minus 10 divided by 3 square.
01:11
And simplifying this, we're going to get 9 times 1 .2 times 4 .5 divided by 3 square.
01:19
And this comes out to be 5 .4 times 10 raised to minus 1.
01:25
That's 0 .54 newton's.
01:29
And similarly, we observed that because of this charge q3, it will experience a repulsive force because both the charges are positive.
01:39
And here we take the direction into consideration.
01:42
And before that, let's convert this f2 vector in terms of vector.
01:47
So it will be f2 vector as 0 .54.
01:51
And as it is along the negative x direction, so it's minus i cap.
01:56
And let's say this is f3.
01:58
So we project this f3, but we observe that this angle is 45 degrees because we just observe this triangle.
02:06
The perpendicular and the adjacent, they are of same length.
02:09
So using tan ratio, we determined this angle as 45.
02:13
So even this will be 45 degree because of vertically opposite angle.
02:17
So when we take its component, we're going to get f3 cost 45 degrees and f3 sign 45 degree in the negative y direction.
02:28
And now we can first figure out the magnitude of this force f3, which will be 9 times 10 raised to 9 times the product of the two charges.
02:36
That's 1 .8 times 4 .5 times 10 raise to minus 10 divided by the square of separation.
02:44
So to get this separation, we just use pythagoras rule for this right angle triangle, right angle at this point where charge q2 is kept.
02:53
So when we use pythagoras rule, we're going to get root of 3 square plus 3 square.
02:58
So that will be root 18.
03:00
And when we square, we're going to get 18...