0:00
Hi there.
00:01
Here we have to solve two problems and in the first one i presume that we have to find magnitude in the direction of the net electrostatic force on charge q1.
00:11
That is what i can read if it's not q1 please submit this question again because it's very hard to see the number.
00:20
So but anyways q1 is charged negatively q2 is charged negatively and q3 is charged positively.
00:28
So it means that charge 2 at point 1 will create the force that is directing from charge 2.
00:43
So that is f21 because yeah these two forces two charges are repelling and charge 1 will be attracted to charge 3.
00:56
So and that will be f31.
01:00
So it means that the overall total force on charge 1 let's label this f1 is directed to the right so and that equals to sum of two forces created by charge is that equals to f21 plus f31 which is k q2 q1 and here we just take the absolute product divided by d1 squared plus k q1 q3 and again we take the absolute product divided by d2 squared so here d1 is 25 centimeters g2 is 20 centimeters so let's calculate this force it equals to 9 times 10 power by 9 newton meter squared divided by column squared multiplied by q1.
02:15
That is, here we take an absolute value that is 10 .0 times 10 power by negative 6 columns.
02:24
And that is multiplied by q2.
02:28
That is again absolute value, 6 .0 times 10 power by negative 6 columns divided by 0 .25 meters squared, plus 5 .0 times 10 powered by negative 6 columns divided by 0 .20 meters that's squared.
02:52
So let's calculate this force.
04:16
So that equals to 19 .89 newtons, which is roughly 20 newtons.
04:27
So that's 20 newtons and directed to the right.
04:36
So now, now, let's we have to, let's move on to the next problem where we need to determine the direction as an air force on charge q1.
04:49
So then we also have to draw the free body diagram.
04:54
So let's start with this diagram.
04:57
So here we have points three, two and one.
05:06
So q1 and q2 are opposite charges.
05:11
That's why they will be attracting to each other.
05:13
So q, f2 .1 will be directed to the right, sorry, to the left.
05:23
And q3 and q1 are the same positive charges.
05:28
That's why they will be repealing, repulsing.
05:32
So it means that f31 is directed at least.
05:37
And that means that the overall sum of these two forces can be shown as following that is this vector f1 so to make our life a little bit easier let's find y and x yeah let's introduce x and y xx and we'll calculate the components of yeah we'll calculate the components of this total force and then we'll calculate the sum so let's start with calculating f2 1 f2 1 equals to negative k u1 q1 q2 that's an absolute value divided by d1 squared and so here both distances are 3 meters so it will make yeah it will actually make our life a little bit easier so let's calculate this force that equals to negative 9 times 10 power by 9 newton meter squared over column squared times q1 that is 1 .2 times 10 power by negative 5 oh sorry that is q2 columns times q1 that is 4 .5 times 10 power by negative 5 columns and that is divided by 3 .0 meters that is squared so let's calculate this number that equals to negative 0 .50 so let me double check my calculation.
08:08
Yeah, negative 0 .54 units.
08:13
So now let's calculate f31 and so let's to calculate, yeah, let's calculate the overall force f31.
08:23
F31, the absolute value of this force equals to k, q1, q1, 3, divided by the distance that is let's label this distance as g3 and d3 equals to d1 times squared of two because that is both distances are equal so it means that d3 squared equals to d1 squared times two so this force equals 9 times 10 power by 9 newton meter squared over column squared multiplied by 1 .8 times 10 powered by negative 5 columns multiplied by 4 .5 times 10 powered by negative 5 columns and that's divided by 2 times 3 .0 meters that is squared so let's calculate it so that equals to 0 .45 neutons so and let's leave all the decimates canal will run later.
10:16
So now we have to find the angle which is formed by in this triangle.
10:23
So and that's a right triangle with equal cut it.
10:28
That's why this angle alpha equals to 45 degree...