00:01
In the quotient we have to find the value of resistance and the value of reactance.
00:05
So, we know that power taken per phase will be equal to total power upon 3.
00:20
So, this will be equal to 14 .4 kilowatt upon 3 which is equal to 4 .8 kilowatt and in watt we will multiply for converting it into watt we will multiply 4 .8 with 1000.
00:36
So, this will be equal to 4800 watt.
00:41
Now, we have vl is equal to 400 watt 400 volt which is equal to v phase and we have il is equal to 34 .65 ampere.
01:02
So, we can further write this as v of phase will be equal to il upon under root 3.
01:12
So, on putting the values we will get 34 .65 upon under root 3 which is equal to 20 ampere.
01:21
Now, impedance per phase will be equal to v upon i.
01:34
So, this is equal to 400 upon 20.
01:38
So, 0 will get cancelled by 0 and we know that 220 times is 40.
01:44
So, we have 20 ampere.
01:45
Now, power per phase will be equal to 4800 and so this will further equal to voltage multiply by current multiply by cos phi.
02:03
So, from here cos phi will be equal to 4800 upon putting the values of v and i we will get 400 upon 4800 upon 400 multiply by 20...