Question

Three identical point charges with charge q = +7.0 nC are placed at each vertex of an equilateral triangle ABC. If the side of the equilateral triangles is 0.07 m, find the resultant electric force on charge at vertex B. A 9 x 10^-5 N B 1.56 x 10^-4 N C 9 x 10^-3 N D 1.4 x 10^-2 N

          Three identical point charges with charge q = +7.0 nC are placed at each vertex of an equilateral triangle ABC. If the side of the equilateral triangles is 0.07 m, find the resultant electric force on charge at vertex B.

A 9 x 10^-5 N
B 1.56 x 10^-4 N
C 9 x 10^-3 N
D 1.4 x 10^-2 N

Three identical point charges with charge q = +7.0 nC are placed at each vertex of an equilateral triangle ABC. If the side of the equilateral triangles is 0.07 m, find the resultant electric force on charge at vertex B.

A 9 x 10^-5 N
B 1.56 x 10^-4 N
C 9 x 10^-3 N
D 1.4 x 10^-2 N

Added by Eric L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

01/07/2022

Step 1

Given: Charge q = +7.0 nC Distance between charges = 0.07 m Using Coulomb's law: \[ F = \frac{k \cdot q^2}{r^2} \] where: F = electric force k = Coulomb's constant = \( 9 \times 10^9 \, Nm^2/C^2 \) q = charge = \( 7 \times 10^{-9} \, C \) r = distance between Show more…

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