00:01
Here three particles are placed in a line and the left particle has a charge of negative 55 microculems.
00:09
The center part, the middle particle has a charge of 45 microculems.
00:17
And the right particle has a charge of negative 78 microculems.
00:26
So the middle particle is separated from each particle by 72 centimeters.
00:32
And here we first have to calculate net force on the middle particles and then net force on the right particle.
00:53
Let's show it.
00:55
So here we have three particles minus 55 or actually let's label them one, two and three.
01:10
One, two and three.
01:12
Particle one has a negative charge.
01:15
Particle two has a positive charge.
01:16
Particle two has a positive.
01:17
Charge particle 3 has a negative charge so let's introduce the x -axis and let's first solve problem 8 we have to calculate the force exerting on the middle particle so this force is a sum of two forces created by the first particle and by the second particle so the first particle it has the opposite charge that's why the force will be attraction.
02:01
So that is f2 -1.
02:04
And the second charge, sorry, the third charge is also has a negative sign.
02:12
That's why it will be also attracting the second particle.
02:16
That is, that will, that will be f -2 -3.
02:26
So therefore, the overall force in question a is the sum of these two forces.
02:38
Let's project it on the x -axis.
02:41
So this force f equals to f -2 -3 minus f -2 -1.
02:46
F -2 -3 equals to k -q2 -2 -3 divided by it squared, and f -2 -1 equals to k -q -2 -q1 divided by a squared.
03:01
Let's simplify this expression so that becomes k -p2 divided by a squared, multiplied by q3 minus q1 and here i have to state that we should be using the absolute value for for these charges because i've already taken in three counters sign by adjusting the direction so now let's calculate this value so this label this let's label this force as f8 that equals to 9 times 10 power by 9 udon meter squared per coulum squared times q2 that is 45 times 10 power by negative six columns divided by 72 centimeters that is 0 .72 meters squared and that is multiplied by u3 minus u1 that is 78 minus 55 times 10 power by negative 6 now let's complete this calculation...