00:01
In this example, we're going to be looking at the electric field produced by a system of point charges.
00:08
Okay, all of our point charges lie along the x -axis, right? and we're going to be looking at the field on a point on the x -axis.
00:16
Okay, so we have three charges.
00:19
One is located at, and let me just draw, here's our origin.
00:24
This is my positive x direction.
00:26
Each one of these boxes is going to be equal to 0 .1 meter.
00:34
Okay, so i have one point charge at the origin, and that has a magnitude q1 equals 5 .0 nanocoulombs.
00:48
I have charge q2 located at 0 .08 meters.
00:53
So, one, two, three, four, seven, eight.
00:58
So, that's q2, and that equals 3 .0 nanocoulombs.
01:08
And then i have a third charge q3 at negative 5 .5 meters x, and that has a charge of negative 4 .0 nanocoulombs.
01:20
So, we have one, two, three, four, five.
01:27
Q3 equals negative 4 .0 nanocoulombs.
01:34
And i want to find the field at a point way far out.
01:38
I want to find the field at a point p equals 4 .5 meters.
01:49
Okay, so i know for point charges on the electric field follows the superposition principle, which has that the electric field at a point is just due to the sum of the individual fields.
02:01
Okay, so my e at point p, i'll call that e sub p, is going to equal e from charge 1 plus the field from charge 2 plus the field from charge 3...