00:02
Hello student, here we have an equilateral triangle and we have charge q1, q2, q3.
00:16
Q1 equals to 1 microcoulomb, q2 equals to 1 microcoulomb and q3 equals to minus 1 microcoulomb.
00:30
Now the electric field at the midpoint q2, the charge q1 will be along this direction and the electric field q2, q2 at this point will be along this direction.
00:52
Now their horizontal component will cancel out because they are equal in magnitude and only the vertical component will survive.
01:04
So the vertical component, so the resultant electric field due to q1 and q2 will be 2 into k where k is 1 by 4 pi epsilon 0 into 1 into 10 to the power minus 6 divided by this distance is l by root 3 square where l is the length of each side into cos of 60 degree because this is the vertical component.
01:34
So this is equals to 3k into 10 to the power minus 6 divided by l square.
01:40
Now due to this charge q3, the electric field will be along this direction.
02:02
Now electric field q2, q3 will be k into 1 into 10 to the power minus 6 divided by l by root 3 whole square.
02:15
This is 3k into 10 to the power minus 6 divided by l square.
02:21
So net electric field will be 2 into 3k into 10 to the power minus 6 divided by l square.
02:30
So this is equals to 13 .5 into 10 to the power 3 newton per coulomb.
02:44
Now here the electric field is along the line joining the center and the charge q3.
02:51
The direction of the field is this is the direction of the field.
03:00
Now the potential at the center will be k into q1 by l by root 3 plus q2 by l by root 3 plus q3 by l by root 3.
03:17
L is the length of the side...