tne population in thousands of certain city from 2ooo through 2014 can be moceled by population

So the formula for population is given. When we plug in the given values, we are able to solve f

The population of a town can be modeled by the function P equals 110 .6E to the KT. T equals zer

All right, so they give you this equation, 110 .2e to the kt power. And what we know is that eig

Okay, so I can see from your work that you've got part of it, but let's talk about the work that

Question

The population (in thousands) of a certain city from 2000 through 2014 can be modeled by the population function P(t) = 130âˆš(t - 2000) + 161.050. Find the value of k (Round your answer to four decimal places). (a) Is the population increasing or decreasing? Explain. The population is increasing because the value of k is positive. (b) Use the model to predict the populations of the city (in thousands) in 2020 and 2025. (Round your answers to three decimal places.) 2020: 130âˆš(2020 - 2000) + 161.050 = 130âˆš20 + 161.050 = 130âˆš20 + 161.050 â‰ˆ 177.320 thousand people 2025: 130âˆš(2025 - 2000) + 161.050 = 130âˆš25 + 161.050 = 130âˆš25 + 161.050 â‰ˆ 186.050 thousand people Are the results reasonable? Explain. The populations are reasonable if the city continues to increase at the same rate from the year 2020 to 2025. According to the model, during what year will the population reach 252,000? To find the year when the population reaches 252,000, we can set up the equation 252 = 130âˆš(t - 2000) + 161.050 and solve for t.

          The population (in thousands) of a certain city from 2000 through 2014 can be modeled by the population function P(t) = 130âˆš(t - 2000) + 161.050. Find the value of k (Round your answer to four decimal places).

(a) Is the population increasing or decreasing? Explain.
The population is increasing because the value of k is positive.

(b) Use the model to predict the populations of the city (in thousands) in 2020 and 2025. (Round your answers to three decimal places.)
2020: 130âˆš(2020 - 2000) + 161.050 = 130âˆš20 + 161.050 = 130âˆš20 + 161.050 â‰ˆ 177.320 thousand people
2025: 130âˆš(2025 - 2000) + 161.050 = 130âˆš25 + 161.050 = 130âˆš25 + 161.050 â‰ˆ 186.050 thousand people

Are the results reasonable? Explain.
The populations are reasonable if the city continues to increase at the same rate from the year 2020 to 2025.

According to the model, during what year will the population reach 252,000?
To find the year when the population reaches 252,000, we can set up the equation 252 = 130âˆš(t - 2000) + 161.050 and solve for t.

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