Question

To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of the pole after 0.50 s and then reaches the top of the pole again after a total elapsed time of 4.1 s. How high is the pole above the point where the ball was launched? (You can ignore air resistance.)

          To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of the pole after 0.50 s and then reaches the top of the pole again after a total elapsed time of 4.1 s. How high is the pole above the point where the ball was launched? (You can ignore air resistance.)
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of the pole after 0.50 s and then reaches the top of the pole again after a total elapsed time of 4.1 s. How high is the pole above the point where the ball was launched? (You can ignore air resistance.)
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To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of the pole after 0.50 s and then reaches the top of the pole again after a total elapsed time of 4.1 s. How high is the pole above the point where the ball was launched? (You can ignore air resistance.)

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To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of the pole after 0.50 s and then reaches the top of the pole again after a total elapsed time of 4.1 s. How high is the pole above the point where the ball was launched? (You can ignore air resistance.)

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Transcript

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00:01 Okay, so we have a person throwing a ball straight up next to a flagpole we want to see the height of the pole above the point where the ball is launched.
00:10 So that is this distance here, which i will call h i'm going to call positive y up and positive x to the right.
00:25 So for simplicity i'm going to put the starting height of the ball to be zero.
00:30 Okay, so at this point the height is h so we have that y at t equals 0 is 0 y at t equals 0 .5 seconds is h and y at t equals 4 .1 seconds is h and we also know that gravitational acceleration is acting downward so there is acceleration equal to negative g i'm going to use the kinematic equation delta y equals v naught t where v naught is the initial speed in the y direction plus 1 half a t squared so we have that delta y the change in the y position from 0 to half a second is equal to delta y from 0 to 4 .1 seconds so we can set those equal to each other.
01:34 So we have v naught times 0 .5 seconds plus 1 half a which is negative g times 0 .5 seconds squared is equal to v naught times 1 4 .1 seconds plus 1 half times negative g times 4 .1 seconds squared...
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