Question

To evaluate the integral $\int \ln(86x) \, dx$ using integration by parts, we would choose $u = \ln(86x)$, $dv = $ $du = \frac{1}{x} dx$, $v = $ Then the integral may be re-expressed as: $ $and then finally we get $\int \ln(86x) \, dx = $

          To evaluate the integral $\int \ln(86x) \, dx$ using integration by parts, we would choose
$u = \ln(86x)$, $dv = $
$du = \frac{1}{x} dx$, $v = $
Then the integral may be re-expressed as:
$
$and then finally we get $\int \ln(86x) \, dx = $

To evaluate the integral ∫ln(86x) dx using integration by parts, we would choose
u = ln(86x), dv =
du = (1)/(x) dx, v =
Then the integral may be re-expressed as:
and then finally we get ∫ln(86x) dx =

Added by Jason B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sam Stansfield

02/18/2024

Step 1

Step 1: Choose u and dv For the integral \int ln(86x)dx, we would choose: u = ln(86x) (to differentiate) dv = dx (to integrate) Show more…

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To evaluate the integral int ln(86x),dx using integration by parts, we would choose u= dv= du=(1)/(x)dx,v=◻ Then the integral may be re-expressed as: ◻ and then finally we get int ln(86x)dx= ◻ To evaluate the integral In(86).dx using integration by parts, we would choose 1n(86x) dv= u du= dx Then the integral may be re-expressed as: and then finally we get/In(86) d