To obtain the final expression for $f'(t)$, simplify the expression. $f'(t) = \frac{t^6(-\sin t) - \cos t(6t^5)}{(t^6)^2}$ $= -\frac{t^6(\sin t) + \cos t(6t^5)}{t^6\sin(t) + 6t^5\cos(t)}$ $= -\frac{t^6\sin(t) + 6t^5\cos(t)}{t^{12}}$
Added by Michael C.
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Step 1
The initial expression is: $f'(t) = \frac{t^6(-\sin t) - \cos t(6t^5)}{(t^6)^2}$ Step 2: Simplify the numerator. $t^6(-\sin t) - \cos t(6t^5) = -t^6\sin t - 6t^5\cos t$ Step 3: Simplify the denominator. $(t^6)^2 = t^{6 \times 2} = t^{12}$ Step 4: Substitute the Show more…
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