To obtain the total scattering cross section ?, we first compute the scattering amplitude f(?) = -frac{2m}{hbar^2 ?} int_0^infty r V(r) sin(? r) , dr where ? = 2k sinleft(frac{?}{2} ight) Substituting Gaussian potential of the form V(r) = A e^{-? r^2}, Therefore, f(?) = -frac{2mA}{hbar^2 ?} int_0^infty r e^{-? r^2} sin(? r) , dr = -frac{2mA}{hbar^2 ?} int_0^infty frac{d}{dr}left(-frac{1}{2?} e^{-? r^2} ight) sin(? r) , dr = frac{2mA}{2? hbar^2 ?} left{left[e^{-? r^2}sin(? r) ight]_0^infty - int_0^infty e^{-? r^2} frac{d}{dr}[sin(? r)] , dr ight} = frac{mA}{? hbar^2 ?} left{0 - ? int_0^infty e^{-? r^2} cos(? r) , dr ight} = -frac{mA}{? hbar^2} left{frac{sqrt{pi}}{2sqrt{?}} e^{-frac{?^2}{4?}} ight} = -frac{mAsqrt{pi}}{2hbar^2 ?^{3/2}} e^{-frac{?^2}{4?}}
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We are given the scattering amplitude formula: f(0) = 2m ∫ rV(r) Jsin(kr) dr / (h_bar k) Show more…
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Use the Born approximation to determine the total cross-section for scattering from a gaussian potential $$ V(\mathbf{r})=A e^{-\mu r^{2}} $$ Express your answer in terms of the constants $A, \mu$, and $m$ (the mass of the incident particle), and $k \equiv \sqrt{2 m E} / \hbar$, where $E$ is the incident energy.
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