00:03
In order to answer this question, let's talk about transcription and translation.
00:09
It's transcription and translation of a gene resource in a polypeptide that is only 5 amino acids total.
00:15
Answer the following, each question is intended to lead you step by step.
00:20
The table of amino acids is included below for reference.
00:22
Well, in the question provided, there is no...
00:26
There is not a table of amino acids, but anyway, you can find that on internet by just writing in a genetic code, and you're going to find that.
00:34
A table that has all the amino acids in each codon that code for.
00:41
So it says, how many codons will be needed to synthesize 5 amino acids, a 5 amino acid polypeptide from start to finish? so remember that when you have a triplet of nucleotides, for example, if you have a ug, cga, this sequence of nucleotides, when you group one, a, a, you group one, a, a, a, you have a, a, a, you have a, three nucleotize in a group of three, this is called a codon.
01:14
Okay, so if you have a if you have five amino acids and as i told you one codon goes for one amino acid, it means how many columns are required for five amino acids? then you can just multiply this by five and you're gonna and you're gonna have that five columns are required to produce five amino acids and each column has three nucleotides so you would require 15 nucleotides to produce 500 acids but they are asking you the number of cottons only okay the next question says what will be the first cotton sequence in the messenger rna and first amino acid that is used to start as in the disorder 14 so you have many columns but there is one cotton that is known as the star cotton and that a condom is a u.
02:06
Okay this is the star codon and this a cotton codes for the amino acid metionine.
02:16
The next question says, when dna is transcribed, the temporary strand is great in that, and while the template is straight is great in the 3 to 5 detection, and it is in that the rna strand is synthesized in the 5 to 3 direction.
02:37
Okay, from the 5 end to the 3 end.
02:41
The next question says, therefore what will be the sequence of the first codon found in the temporary strand? so remember based pairing rules.
02:47
Base per ingles say that adenine pairs with thymine in dna but with uracillin rna, hence it doesn't always pairs with warning.
02:57
So remember also that you have two strands in your dna.
03:04
This is the coding strand of dna, also known as anti -templary strand, and this is a template strand.
03:10
They are complementary to each other following base peringules.
03:13
And also, this template strand is going to produce a messenger rna.
03:18
And this messenger rna is complementary to a temporary to a temporary so as you can see, both the coding strength of dna and the messenger rna are complemented to a template strand.
03:26
So it means that the coding strength of dna and the messenger rna both have the same sequence, with the only difference that the coding has cyming because it is dna and the messenger rna has uracil.
03:41
So it says, what will be the sequence of the first code on found in the template strand? so the start codon in the messenger rna, as i told you, was.
03:52
A .u.
03:52
So you have here a .u.
03:55
And as a .u .g is complementary or tamla is complementary to a template.
03:59
Then the start codon in the temple would be, following by experience.
04:04
You have t, a, c.
04:08
Okay, because a is complementary to timing euracil with adeline and one in with cytosine.
04:15
The next question says, what will be the sequence of the first codon in the non -template strand? so the the non -templary strand is the same as the coding and as i told you it has the same sequence as the messenger rna with the only difference that you have timing here instead of uracil.
04:33
So if you have here ag, then you have here atg.
04:40
The next question says, this double -stranded dna molecule below produces the polypeotating question.
04:45
Using the following information or using the information in the questions above a to e answer the following.
04:51
So you have here strand x and strand y.
04:54
Now it says, x or y.
04:56
Which strand is a template strand and which is a non -templary strand...