Turn on your desk lamp. Pick up the cord, with your thumb...

Turn on your desk lamp. Pick up the cord, with your thumb and index finger spanning the width of the cord. (a) Compute an order-of-magnitude estimate for the current in your hand. You may assume that at a typical instant the conductor inside the lamp cord next to your thumb is at potential $\sim 10^{2} \mathrm{V}$ and that the conductor next to your index finger is at ground potential $(0 \mathrm{V}) .$ The resistance of your hand depends strongly on the thickness and the moisture content of the outer layers of your skin. Assume that the resistance of your hand between finger- tip and thumb tip is $\sim 10^{4} \Omega$ . You may model the cord as having rubber insulation. State the other quantities you measure or estimate and their values. Explain your reasoning. (b) Suppose that your body is isolated from any other charges or currents. In order-of-magnitude terms describe the potential of your thumb where it contacts the cord, and the potential of your finger where it touches the cord.

Transcript

00:01 As shown in the figure, we have a power source and from the power source a code is running.

00:10 The code is having two conductor inside, a red conductor and a blue conductor.

00:16 A switch as is in the on condition and the code is finally connected to the bulb, bulb of the dusk lamp.

00:27 Right now on the code we have a point a and point b inside the code we have two conductors we have two wires point a is the point on the wire which is touching to the thumb we are holding the the code in such a way that the one end of the code at point a is touching our thumb and the other end of the wire at point b is stretching our index finger.

01:03 So we are holding the wire as shown here.

01:08 You can see the point b is here at the index finger and point a is connected to the is touch with the thumb.

01:20 Now as per the given problem, the point a where the code is touching the thumb has a potential of 10 -res to 2 volt, right? and the point b, where index finger is touching the thumb, the potential is 0 volt.

01:40 And in the given problem, it is said that the, the means resistance of the hand between the thumb and the index finger, means resistance of all this part of the hand, its resistance is 10 to 4 oms right so point a is at a potential of 10 to 2 volt point b which is the index finger is at a potential of 0 volt so because of the potential difference between thumb and the hand the current will flow say from thumb to hand right because current flows say from higher potential to the lower potential so means current will flow say from thumb to hand this way the current will flow this way right so we are supposed to find out the current we know the current i is equal to potential difference now here potential difference is potential difference between thumb and the index finger.

03:10 This is va minus vb upon the resistance.

03:13 Resistance is given as 10 -rest to 4 -home.

03:18 Here it is given.

03:19 And v -a minus v -b, va is 10 -rest -to -2 -volt and v -b is 0 -volt, right? as we can see, va here is 10 -res to 2 volt at thumb and vb is 0 -volt and divided by 10 -res -to -4.

03:42 So, this current flowing through the hand is 10 -rest -2 upon 10 -rest -4...

Question

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