Question

Tutorial Q2. By regarding \(\vec{OA} = 3\hat{i} + 2\hat{j} + \hat{k}\) and \(\vec{OB} = \hat{i} + 2\hat{j} - 3\hat{k}\) as position vector and vector along the line respectively and vice versa, write two vector equations and hence, determine the point of intersection of these two lines. Hence, discuss why lines formed in such format can have solution for intersection.

          Tutorial
Q2. By regarding \(\vec{OA} = 3\hat{i} + 2\hat{j} + \hat{k}\) and \(\vec{OB} = \hat{i} + 2\hat{j} - 3\hat{k}\) as position vector and vector along the line respectively and vice versa, write two vector equations and hence, determine the point of intersection of these two lines.
Hence, discuss why lines formed in such format can have solution for intersection.

Tutorial
Q2. By regarding O⃗A⃗ = 3î + 2ĵ + k̂ and O⃗B⃗ = î + 2ĵ - 3k̂ as position vector and vector along the line respectively and vice versa, write two vector equations and hence, determine the point of intersection of these two lines.
Hence, discuss why lines formed in such format can have solution for intersection.

Added by Jose Ignacio S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Shyam P

06/01/2022

Step 1

The vector equation for line OA can be written as: r = a + t * d where r is the position vector of any point on the line, a is the position vector of a point on the line (in this case, OA), t is a scalar parameter, and d is the direction vector of the line. Given Show more…

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Tutorial Q2. By regarding OA = 3i + 2j + k and OB = i + 2j -- 3k as position vector and vector along the line respectively and vice versa, write two vector equations and hence, determine the point of intersection of these two lines. Hence, discuss why lines formed in such format can have solution for intersection.