00:01
For this question, we consider a scenario where two cards are drawn at random from a deck of 52, and for part a we are asked for the probability that at least one card is an ace.
00:26
Now, it's simpler to solve the probability that none of the cards are aces.
00:31
So we can re -express this as 1 minus, the probability of no aces.
00:43
And for this probability, we can use the classic approach to probability, which says that the probability of a given event, in this case it's the event of getting no aces in the two randomly selected cards, is equal to the number of outcomes in the sample space that result in getting no aces, divided by the total number of outcomes in the sample space.
01:11
So what is meant by that is the total number of outcomes in the sample space is the total number of ways of drawing two cards from a deck of 52.
01:20
There are 52 cards, and we are drawing 2.
01:24
So the total number of ways to get 2 is 52 choose 2.
01:29
The total number of ways to get no aces.
01:32
There are 4 aces in the deck, so that means there are 48 cards that are not aces, and we need to choose 2...