00:01
Hi, today we are solving the question in which two cars are moving towards an intersection.
00:07
So one car is moving at 160 meters north, that is 20 meter per second towards interaction.
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And the other one, that is the second car, is moving at 70 meter west.
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And 16 meters away from the intersection.
00:40
So three seconds later, the distance between the car is the hypotenuse of a right triangle.
00:46
So from here, s square is equal to x square plus y square.
00:53
Now taking the derivative of both sides of the equation and dividing by s.
00:58
So here, s dash is equals to x xx dash plus y, y, dash, and dividing by 2 so here we will get s divided by s so three second later one car is 100 meter north of intersection three second later one car will be at 100 meter north and 20 meter per second and second car will be at 118 meter west of intersection at 16 meter per second...