00:01
In this problem, we have been given that there are two charges plus six microculum, each which are placed at a distance of four centimeters on either side of this origin.
00:12
And also there are another two charges, one of three microculum, and another one which is minus eight microculum, and they are placed at a distance of five and seven centimeters in y -axis.
00:24
So we need to determine the net electric field, including the magnitude and the direction, because of all these charges at the origin.
00:34
So we observed that the expression to get the electric field is kq by r square.
00:38
And here the electric field because of these six microculum charges that will cancel each other because we know the direction of electric field is away from the positive charge and towards the negative charge.
00:51
So only electric field that will be here at this origin will be because of three microculum.
00:57
Let's say the electric field is e3, which will of course be directed below the origin, add the electric field because of minus 8 microculum, let's say it is e8, which will be directed in the positive wide direction.
01:12
So we represent the positive y direction with the j -cap here, and we can compute the electric field because of three microculum charge, so that will be k, which is 9 into 10 raise to 9 times the magnitude of charge.
01:25
That's 3 into 10 raised to minus 6 column upon the square of the distance.
01:30
That's 0 .05 in terms of meters.
01:33
So we square it...