00:01
Hello students, let's consider the figure and calculate the moments of area.
00:05
Therefore, we can write 5a plus 4a into t plus y bar is equal to 5at into 3a by 2.
00:18
Therefore, y bar is equal to 5a by 6.
00:23
Now to calculate the moment of area about the x -axis i .e.
00:29
I -axis will be equal to 4at into 5a divided by 6 the whole square plus 5a the whole cube into t into 3 by 5 the whole square divided by 12 plus 5at into 2a divided by 3 the whole square.
00:53
Therefore, we will get i -axis will be equal to 165 divided by 12 into a cube into t.
01:04
Secondly, we can find out what is iyy.
01:09
It is 4a the whole cube divided by 12 into t plus 5a the whole cube into t into 4 by 5 the whole cube sorry whole square divided by 12.
01:29
We will get iyy will be equal to 12 into a cube into t.
01:37
Thirdly, let's find out ixy and it is equal to 5a the whole cube into t into 3 by 5 into 4 by 5 divided by 12.
01:57
Hence, ixy is 5a cube t.
02:03
Now let's write the equation for maximum bending moment i .e.
02:09
My maximum is equal to omega into t square divided by 8.
02:17
Here, mx is equal to 0.
02:20
Let's consider the equation for direct stress i .e.
02:24
M by i is equal to sigma x divided by y...