00:01
In the given question, the f1 individuals given are heterozygous for both the genes, that is, capital g, small g, capital l, cross another heterozygous individual.
00:13
So the gametes produced from these individuals will be capital g, capital l, small g, capital l, then capital g small l and small g small l.
00:27
So if we draw the ponit square for these cross, it will be like this.
00:36
So here from one individual, the gametes will be gl, small g, capital l, and the recessive ones.
00:47
These one here g l, g l, capital g l, small g, small l.
00:55
So first offspring here will be capital g g l, dominant for both.
01:01
And next one here will be heterozygous for g, homozygous for capital l, then homozygous for capital g and heterozygous for l...