00:01
Hi, in this question we have two identical blocks having masses 3kg.
00:06
So we have m1 equals to m2 equals to m given as 3kg.
00:12
So if we try to figure it out, we have one block and there is another block and these two are stacked like this.
00:23
So mass is m1 and m2.
00:25
Also, this bottom block is free to slag.
00:31
On this frictionless surface and the coefficient of static friction between the block is given as mu equals to 0 .35.
00:42
So we have to calculate the maximum horizontal force that can be applied to this lower block without the upper block slipping.
00:53
So first of all, we'll assume that the external force moves the block without slipping with a common acceleration a, then from newton's equation we have force equals to mass into acceleration.
01:12
So if acceleration is ac, so we can calculate ac as force f divided by mass, which will be 3 plus 3...