00:01
Not to answer this question, let's talk about inheritance.
00:02
It says two individuals are made with the father's genotype being homocygous dominant for a, heterocygoyles for b, and homocygousous recessive for c, and the mother's genotype being heterocygoyles for a, heterocygoyles for b, and heterocycaryth, and heterocygoyles for c.
00:19
So this is true cross.
00:21
And it says, what is the probability that the offspring will be? heterocygocos a, homozygouseliminal v, and heterocygous you want this genotype okay and it says you don't need to do a target cross and well this is true because in this case you can make three monohybonyl hybrid panel squares crossing the homozygous dominant a with the heterocyglocius a the heterocygous b with the heterocygous b and this c with this c so in this case you have to following monohyrihyb monohyroid panel squares homohygous diagonal this and this then you have heterocygoyles with the heterocygios b, and you get the following genotypes.
01:10
And finally, the homocyco decisive with the heterozygotes.
01:14
You get heterozygos, heterocycos, homocygousycese, and homocygotech.
01:19
So you want to get heterocygous a.
01:22
So out of four possibilities, one and two are heterozygos a.
01:25
So you have two quarters, and two quarters is the same as one half...