00:01
Let's discuss this question.
00:01
So a single slit 0 .03 millimeter width is illuminated by the light from the c -u -a -r laser.
00:08
So we need to find what is the screen distance, what is the angle of the second bright, what is the maximum order observed and what is the separation between third and fourth dark fringes.
00:20
So here lambda is given as 680 nanometer over here.
00:26
A, that is, y1 is equal to 0 .2.
00:30
2mm that will be equal to 2 multiplied by 10 x to minus 4 meter.
00:36
Here d, sine theta is equal to n lambda where n is equal to 1.
00:43
So, sine theta will be equal to 680 multiplied by 10 raise to minus 9 divided by 3 multiplied by 10 raise to minus 5.
00:53
So here we can say this will be equal to 0 .0227.
01:00
So as l is equal to y1 divided by sine theta, this will be equal to 8 .824 multiplied by 10 raise to minus 3 meter...