Question

Two parallel plates have capacitance 30 µF when they are separated by air. These plates are connected to a battery of voltage 1.5 V and fully charged, then a glass sheet of dielectric constant 5 which fits tightly between the plates is inserted. How does the potential energy stored in the capacitor change when the glass sheet is inserted?

Name: Two parallel plates have capacitance 30 µF when they are separated by air. These plates are connected to a battery of voltage 1.5 V and fully charged, then a glass sheet of dielectric constant 5 which fits tightly between the plates is inserted. How does the potential energy stored in the capacitor change when the glass sheet is inserted?
Uploaded: 2023-06-26T10:19:32-08:00
Duration: 1 min 48 s
Channel: Adi S
Description: Two parallel plates have capacitance 30 µF when they are separated by air. These plates are connected to a battery of voltage 1.5 V and fully charged, then a glass sheet of dielectric constant 5 which fits tightly between the plates is inserted. How does the potential energy stored in the capacitor change when the glass sheet is inserted?

          Two parallel plates have capacitance 30 µF when they are separated by air. These plates are connected to a battery of voltage 1.5 V and fully charged, then a glass sheet of dielectric constant 5 which fits tightly between the plates is inserted. How does the potential energy stored in the capacitor change when the glass sheet is inserted?

Two parallel plates have capacitance 30 µF when they are separated by air. These plates are connected to a battery of voltage 1.5 V and fully charged, then a glass sheet of dielectric constant 5 which fits tightly between the plates is inserted. How does the potential energy stored in the capacitor change when the glass sheet is inserted?

Added by Gregory W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/26/2023

Step 1

Step 1: The potential energy stored in a capacitor is given by: $$U = \frac{1}{2}CV^2$$ where C is the capacitance and V is the voltage. Show more…

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Two parallel plates have capacitance 30 µF when they are separated by air. These plates are connected to a battery of voltage 1.5 V and fully charged, then a glass sheet of dielectric constant 5 which fits tightly between the plates is inserted. How does the potential energy stored in the capacitor change when the glass sheet is inserted?