Two particles of equal charge after being accelerated through the same potential difference enter a uniform transverse magnetic field and describe circular paths of radii R1 and R2 respectively. Find the ratio of their masses (M1 /M2 ).
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Two particles $X$ and $Y$ having equal charges, after being accelerated through the same potential difference, enter a region of uniform magnetic field and describe circular paths of radii $R_{1}$ and $R_{2}$, respectively. The ratio of masses of $X$ and $Y$ is (A) $\left(\frac{R_{1}}{R_{2}}\right)^{1 / 2}$ (B) $\frac{R_{2}}{R_{1}}$ (C) $\left(\frac{R_{1}}{R_{2}}\right)^{2}$ (D) $\left(\frac{R_{1}}{R_{2}}\right)$
Two particles of equal charge after being accelerated through the same potential difference enter a uniform transverse magnetic field and describe circular paths of radii $R_{1}$ and $R_{2}$ respectively. Then the ratio of their masses $\left(M_{1} / M_{2}\right)$ is $\quad$ [Kerala CET 2008] (a) $R_{1} \overline{/} R_{2}$ (b) $\left(R_{1} / R_{2}\right)^{2}$ (c) $\left(R_{2} / R_{1}\right)$ (d) $\left(R_{2} / R_{1}\right)^{2}$ (e) None of these
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Particle A with charge q and mass mA and particle B with charge 2q and mass mB are accelerated from rest by a potential difference ΔV, and subsequently deflected by a uniform magnetic field into semicircular paths. The radii of the trajectories by particle A and B are R and 2R, respectively. The direction of the magnetic field is perpendicular to the velocity of the particle. What is their mass ratio mA/mB?
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