00:01
All right, so let's say two charges.
00:02
We've got q1, which is two nanoculams, and then q2, which is negative 6 .1 nanoculams, and they're separated by a distance d of 0 .1 meters.
00:15
And point a is halfway between them.
00:17
So the voltage at point a, which is what we're tasked with finding for the first part, is going to be k times q1 over like d over two, minus k.
00:29
It's really plus k.
00:30
K.
00:30
Times q2 over d plus d over 2, but q2 is negative.
00:35
So we'll end up getting a difference between these.
00:40
But if we do this, this should be, you know, write it as 9 times 10 to the 9th newton's times a square meter per coulone squared over 0 .05 meters.
00:53
And then times 2 minus 6 .1 times 10...