Question

Two rods of equal length, one with a uniform positive linear charge density of +1.5 × 10⁻⁹ C/m and the other with a uniform negative linear charge density of -1.5 × 10⁻⁹ C/m, are bent to form semicircles each of radius 0.3 m. These semicircles are then joined to make a full circle. What is the magnitude of the electric field at the center of the circle?

Name: two rods of equal length one with a uniform positive linear charge density of 15 109 cm and the other with a uniform negative linear charge density of 15 109 cm are bent to form semicircles 11798
Uploaded: 2022-05-20T07:51:44-08:00
Channel: Suman K
Description: two rods of equal length one with a uniform positive linear charge density of 15 109 cm and the other with a uniform negative linear charge density of 15 109 cm are bent to form semicircles 11798

          Two rods of equal length, one with a uniform positive
linear charge density of +1.5 × 10⁻⁹ C/m and the other with a
uniform negative linear charge density of -1.5 × 10⁻⁹ C/m,
are bent to form semicircles each of radius 0.3 m. These
semicircles are then joined to make a full circle. What is the
magnitude of the electric field at the center of the
circle?

Added by Dustin F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Suman K

05/20/2022

Step 1

Given: Positive linear charge density, λ = +1.5 × 10^-9 C/m Radius of the semicircle, r = 0.3 m Electric field due to positive charges, E+ = -2kλ/r E+ = -2 * (9 * 10^9) * (1.5 * 10^-9) / 0.3 E+ = -90 N/C (away from the semicircle) Show more…

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Two rods of equal length, one with a uniform positive linear charge density of +1.5 × 10⁻⁹ C/m and the other with a uniform negative linear charge density of -1.5 × 10⁻⁹ C/m, are bent to form semicircles each of radius 0.3 m. These semicircles are then joined to make a full circle. What is the magnitude of the electric field at the center of the circle?