Ship A travels northwest, which is 135 degrees from east. So, the velocity vector of ship A is:
$$v_A = (20\cos(135^\circ), 20\sin(135^\circ)) = (20(-\frac{\sqrt{2}}{2}), 20(\frac{\sqrt{2}}{2})) = (-10\sqrt{2}, 10\sqrt{2})$$
Ship B travels 34 degrees west of
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