00:01
Alright, so let's start off by drawing an image.
00:04
So we have a car traveling south towards the intersection.
00:11
And then we have some sign, radar sign here.
00:16
So we know that the radar sign is one -fourth of a mile east of the intersection.
00:29
And then we know that when the car is exactly half a mile away from the sign, so in this case, half a mile away from the sign.
00:40
A mile then the right here is negative which is decreasing at 60 miles per hour so the rate is negative negative 60 miles per hour so in this case we want to figure out what's true about the distance between a car and the intersection at this instance so in this case why so this is set up like a the thagorean theorem.
01:15
So we're going to have one -fourth squared plus y -squared is equal to one -half squared.
01:33
So in this case, when we simplify this, this is going to give us one -sixteenth plus y -squared equal to one -fourth, or we can write this as four over sixteen.
01:52
So we can have y squared is equal to three over 16 or y is equal to the square root of three over 16 so we want to to know which is true about the following distance between a car and intersection at this moment so we need to find the derivative of our pythagorean theorem so we have two x dx plus two y d y plus two r d r so in this case we know i would need to plug in some bits of information so we have two times the x distance which is one -fourth but the change in x is zero so you're have to worry about that section you have two y which we found y to be we regret this as the square root of three over four so square root of three over four and then we're looking for to change the distance for the car intersection and then two and r we know is one half and then the change in r is negative 60 so let's simplify some components we have two and four turns it to and two, that just turns it to zero.
03:46
So we have square root of three over two, d .y...