00:01
In problem 2 .4, we are solving a question very similar to 2 .3, except we have different magnitudes for the two forces p and q.
00:10
So first, let's look at this question from using the parallelogram law.
00:18
First, we draw all four signs of the parallelogram.
00:21
Sorry, it looks a little bit bad.
00:24
There you go.
00:28
And then the diagonal of the parallelogram is going to be the resultant force, which will name fr.
00:34
And the angle we're looking for of the 4th, we can name it theta.
00:42
So to solve this triangle, the one i'm hiding here, first we need to find the angle that i'm pointing out here.
00:54
And we know that the size 4, and since the two adjacent angles in the parallelogram at up to 180 degrees, and we know one of them, it's 75 degrees, which is from 25 plus 50.
01:11
We know that this angle would be 180 minus 75 degrees, which gives us 105 degrees...