00:01
Hello students, in this question we have two trains.
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One is traveling at a speed of 72 km per hour and another train of 144 km per hour.
00:11
And they are headed towards one another along a straight line.
00:16
So, when they reach the distance of 1 .100 x 10 raised to 3 m apart, the engineer applies the brakes.
00:27
And so the acceleration is negative 1 m per second square opposite to the motion.
00:33
So, we have to calculate distance for train to stop and time taken.
00:48
So, we can use the equation of motion v is equal to, v square is equal to u square plus 2as and v is equal to u plus at here.
01:04
So, if we write u1 is equal to 72 km per hour, we can write which is equal to 20 m per second.
01:19
Similarly, u2 is equal to 144 km per hour that is equal to 40 m per second.
01:29
So, we have v1 and v2 are 0.
01:35
So, we have 0 is equal to 20 square minus 2 into 1 into s1...