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16) Two vectors, \vec{A} and \vec{B}, have magnitudes $|\vec{A}| = |\vec{B}| = 6.00$. Their vector (cross) product is \vec{A} \times \vec{B} = -20.00\hat{i} + 8.00\hat{j}.\newline What is the angle $\theta$ between vectors \vec{A} and \vec{B}, and what is the scalar (dot) product, \vec{A} \cdot \vec{B}? \newline A) $\theta = 17.1^\circ$, $\vec{A} \cdot \vec{B} = 28.84$ \newline B) $\theta = 17.1^\circ$, $\vec{A} \cdot \vec{B} = 34.40$ \newline C) $\theta = 36.8^\circ$, $\vec{A} \cdot \vec{B} = 28.84$ \newline D) $\theta = 36.8^\circ$, $\vec{A} \cdot \vec{B} = 34.40$ \newline E) $\theta = 53.2^\circ$, $\vec{A} \cdot \vec{B} = 28.84$ \newline F) $\theta = 53.2^\circ$, $\vec{A} \cdot \vec{B} = 34.40$ \newline G) $\theta = 0^\circ$, $\vec{A} \cdot \vec{B} = 36.00$

          16) Two vectors, \vec{A} and \vec{B}, have magnitudes $|\vec{A}| = |\vec{B}| = 6.00$. Their vector (cross) product is \vec{A} \times \vec{B} = -20.00\hat{i} + 8.00\hat{j}.\newline What is the angle \(\theta\) between vectors \vec{A} and \vec{B}, and what is the scalar (dot) product, \vec{A} \cdot \vec{B}? \newline A) \(\theta = 17.1^\circ\), \(\vec{A} \cdot \vec{B} = 28.84\) \newline B) \(\theta = 17.1^\circ\), \(\vec{A} \cdot \vec{B} = 34.40\) \newline C) \(\theta = 36.8^\circ\), \(\vec{A} \cdot \vec{B} = 28.84\) \newline D) \(\theta = 36.8^\circ\), \(\vec{A} \cdot \vec{B} = 34.40\) \newline E) \(\theta = 53.2^\circ\), \(\vec{A} \cdot \vec{B} = 28.84\) \newline F) \(\theta = 53.2^\circ\), \(\vec{A} \cdot \vec{B} = 34.40\) \newline G) \(\theta = 0^\circ\), \(\vec{A} \cdot \vec{B} = 36.00\)

16) Two vectors, A⃗ and B⃗, have magnitudes |A⃗| = |B⃗| = 6.00. Their vector (cross) product is A⃗ ×B⃗ = -20.00î + 8.00ĵ.What is the angle θ between vectors A⃗ and B⃗, and what is the scalar (dot) product, A⃗ ·B⃗? A) θ = 17.1^∘, A⃗·B⃗ = 28.84 B) θ = 17.1^∘, A⃗·B⃗ = 34.40 C) θ = 36.8^∘, A⃗·B⃗ = 28.84 D) θ = 36.8^∘, A⃗·B⃗ = 34.40 E) θ = 53.2^∘, A⃗·B⃗ = 28.84 F) θ = 53.2^∘, A⃗·B⃗ = 34.40 G) θ = 0^∘, A⃗·B⃗ = 36.00

Added by Ryan R.

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