[ UCONN 1071Q ] Evaluate the following integral $$ \int \frac{x^3}{(x^4 + 3)^2} dx $$ (A) $$ -\frac{1}{4x^4 + 3} + C $$ (B) $$ -\frac{1}{4x^4 + 12} + C $$ (C) $$ \frac{1}{4x^4 + 12} + C $$ (D) $$ -\frac{1}{x^4 + 3} + C $$ (E) $$ \frac{1}{4x^4 + 3} + C $$
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Step 1: The problem asks us to evaluate the integral: $$ \int \frac{x^3}{(x^4 + 3)^2} dx $$ We can use a substitution method to solve this integral. Show more…
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