Question

Let the total cost function C(x) be defined as follows. C(x) = 3,000 + 3x - 0.0002x^2 Find the marginal average cost function ?'(x). (Hint: Find average cost first.) ? ?'(x) = - 2800 / x^2 - 0.0008 ? ?'(x) = 0 ? ?'(x) = - 3000 / x^2 - 0.0002 ? ?'(x) = 3 - 0.004x

          Let the total cost function C(x) be defined as follows.

C(x) = 3,000 + 3x - 0.0002x^2

Find the marginal average cost function ?'(x).

(Hint: Find average cost first.)

? ?'(x) = - 2800 / x^2 - 0.0008
? ?'(x) = 0
? ?'(x) = - 3000 / x^2 - 0.0002
? ?'(x) = 3 - 0.004x

Let the total cost function C(x) be defined as follows.

C(x) = 3,000 + 3x - 0.0002x^2

Find the marginal average cost function ?'(x).

(Hint: Find average cost first.)

? ?'(x) = - 2800 / x^2 - 0.0008
? ?'(x) = 0
? ?'(x) = - 3000 / x^2 - 0.0002
? ?'(x) = 3 - 0.004x

Added by Melissa P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

09/09/2023

Step 1

The average cost is the total cost divided by the quantity produced, so: A(x) = \frac{C(x)}{x} = \frac{3000 + 3x - 0.0002x^2}{x} Now, we need to find the derivative of the average cost function with respect to x, which is the marginal average cost function, Show more…

Show all steps

Thanks for your feedback!

Let the total cost function C(x) be defined as follows: C(x) = 3,000 + 3x - 0.0002x^2. Find the marginal average cost function C'(x): (Hint: Find average cost first:)