Un neutrone si muove con una velocità iniziale \( v_{\text {in }}= \) \( =5,2 \cdot 10^{5} \mathrm{~m} / \mathrm{s} \) e urta elasticamente una particella \( \alpha \) (un nucleo di elio, la cui massa è circa 4 volte quella del neutrone, \( m_{\alpha} \approx 4 m_{\mathrm{n}} \) ) inizialmente ferma. La particella \( \alpha \) emerge con un angolo di diffusione \( \theta_{\alpha}=42^{\circ} \). Ciò significa che la direzione della velocità finale forma un angolo di \( 42^{\circ} \) con quella della velocità iniziale della particella \( \alpha \). Calcola - l'angolo di diffusione del neutrone; - i moduli delle velocità delle due particelle dopo l'urto.
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We have a neutron colliding with an alpha particle, and we need to find the angle of deflection for the neutron and the final speeds of both particles. ### Step 1: Conservation of Momentum The conservation of momentum in two dimensions can be expressed as: Show more…
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