00:01
Hi, in this question we are given with this reaction in which 4 moles of ammonia react with 5 moles of oxygen gas to produce 4 moles of no and 6 moles of water.
00:11
We are asked to calculate the mass of ammonia that is required to produce 125 gram of water here.
00:21
The percentage yield of no is given as 28 .2 % and it is also given that oxygen is present in excess amount.
00:30
Of all we will calculate the percentage yield of h2.
00:36
It will be equal to 100 minus percentage yield of no.
00:44
We can substitute the values in this manner.
00:47
On solving, we are getting the percentage yield of h2o as 71 .8%.
00:53
Now, we know that the percentage yield is equal to actual yield divided by theoretical yield into 100.
01:14
From here we can calculate the theoretical yield of water.
01:24
It will be equal to actual yield divided by percentage yield into 100.
01:36
Now we can substitute the values here.
01:39
In this manner, on solving we are getting the theoretical yield of water equals to...