Under Hardy-Weinberg equilibrium, if a population exists that contains 2 alleles only, each has a respective frequency: p = 0.3, q = 0.7. Then, after 10 (or 20, or 50, or 100) generations, what will be the resulting frequencies?
Added by Pablo S.
Step 1
3)^2 = 0.09 ** Show more…
Show all steps
Your feedback will help us improve your experience
Shaiju T and 81 other Biology educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A population has two alleles, A and a, and is in Hardy-Weinberg equilibrium. The frequency of allele a is 0.3. What is the frequency of individuals with AA genotype? Hardy-Weinberg equilibrium: p^2 + 2pq + q^2 = 1.
Adi S.
For a population in Hardy-Weinberg equilibrium, in a situation where there are only two alleles at a particular locus, the allelic frequencies are: S=0.7 and s=0.3. Calculate the frequency of the heterozygous genotype in the population.
In a large, randomly mating population, the frequency of an autosomal recessive lethal allele is $0.20 .$ What will the frequency of this allele be in the next generation if all homozygotes die before reproducing?
Recommended Textbooks
Biology for AP Courses
Objective Biology for NEET
Introduction to General, Organic and Biochemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD