00:01
Okay, this question here says, under hardy -wember equilibrium, the genotype frequency of heterozygous individuals is expected to be greatest when the frequency of dominant and recessive alleles are the same.
00:14
Well, so let's check it out.
00:15
In this case, p plus q is equal to 1, remember, where p is the frequency for the alleles that is dominant and q is the frequency for the recessive alleles.
00:24
You also have that p squared plus 2pq plus q squared is equal to 1, where p squared is the frequency of homozygous dominant, 2pq is the frequency of heterozygous, and q squared is the frequency of homozygous recessive.
00:35
Now, in this case, they are asking you, under hardy -wember equilibrium, the genotype frequency of heterozygous individuals is expected to be greatest when the frequency of dominant and recessive alleles are the same.
00:46
So in this case, if they are the same, then it means that p is equal to q.
00:49
So you would have 2p is equal to 1 and p is equal to, if you divide by 2 here, and also here, you're going to get that p is equal to 0 .5.
00:57
And as p and q are the same, then it means that this is equal to 0 .5 and q is also 0 .5.
01:05
So if you find the value for 2pq, you're going to get 2 multiplied by 0 .5 and by 0 .5, and this is going to be equal to 0 .5...