00:01
Of the sickle cell allele, hps.
00:03
So we know that the normal hpa is dominant.
00:07
So they have five children.
00:08
The first two are infected.
00:10
The third has sickle cell anemia.
00:12
The fourth and fifth are not infected.
00:14
What is the probability that the phenotypically normal six child will be a carrier? now, the question here is, the key here is that each child's probability to be a specific genome type is independent from the rest of the other child because each time a child is born, it's not affected by the other children.
00:37
So it doesn't matter if it's six or sevens.
00:41
Each time it's independent.
00:58
So this means that we can actually ignore the first five.
01:01
Now, let's take a look at the sixth child.
01:05
Say the parents are both heterozygous.
01:16
So as you can see that the parents both are hpa, hps.
01:21
Now let's do the punnett square.
01:22
So the two alleles of the parents separate from each other...