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Question 3: A dye suction device is arranged, as shown in Figure 3. The volumetric flow rate of air through the main pipe at circular cross-section (1) is given as $Q = 0.0164 \text{ m}^3/\text{s}$ and the volumetric flow rate of the dye which is sucked from resorvoir A is given as $Q = 0.00082 \text{ m}^3/\text{s}$. The air and the dye flow is mixed in the main pipe and the mixture flow is then sprayed into a material to be dyed at cross-section (3). The pressure at point B where the sucked dye enters into main pipe is given as $0.95P_2$ and the diameter of the suction pipe which connects the reservoir A to the main pipe is $D_1= 1 \text{ cm}$. Determine the manometric (gauge) pressure of reservoir A, $P_A$ and the density of the mixture flow, $\rho_r$ at section (3). The fluids are incompressible and the friction can be neglected. The pressure at Sections (1) and (3) in the main pipe is assumed to be atmospheric except Section (2) and any variation of the velocity over the pipe cross section can be neglected. The diameter of the cross-section (1), $D_1=10 \text{ cm}$, the diameter of the cross-section (2), $D_2= 5 \text{ cm}$, the diameter of the cross-section (3), $D_3= 10 \text{ cm}$, the dye density, $\rho_b= 800 \text{ kg/}m^3$ and air density, $\rho_{air} = 1.2 \text{ kg/}m^3$. The value of gravitational acceleration, g is 9.81 N/kg. (30 Points)

          Question 3:
A dye suction device is arranged, as shown in Figure 3. The volumetric flow rate of air through the main
pipe at circular cross-section (1) is given as $Q = 0.0164 \text{ m}^3/\text{s}$ and the volumetric flow rate of the dye which is
sucked from resorvoir A is given as $Q = 0.00082 \text{ m}^3/\text{s}$. The air and the dye flow is mixed in the main pipe
and the mixture flow is then sprayed into a material to be dyed at cross-section (3). The pressure at point B
where the sucked dye enters into main pipe is given as $0.95P_2$ and the diameter of the suction pipe which
connects the reservoir A to the main pipe is $D_1= 1 \text{ cm}$. Determine the manometric (gauge) pressure of
reservoir A, $P_A$ and the density of the mixture flow, $\rho_r$ at section (3). The fluids are incompressible and the
friction can be neglected. The pressure at Sections (1) and (3) in the main pipe is assumed to be atmospheric
except Section (2) and any variation of the velocity over the pipe cross section can be neglected.
The diameter of the cross-section (1), $D_1=10 \text{ cm}$, the diameter of the cross-section (2), $D_2= 5 \text{ cm}$, the
diameter of the cross-section (3), $D_3= 10 \text{ cm}$, the dye density, $\rho_b= 800 \text{ kg/}m^3$ and air density, $\rho_{air} = 1.2 \text{ kg/}m^3$.
The value of gravitational acceleration, g is 9.81 N/kg. (30 Points)
        
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Question 3:
A dye suction device is arranged, as shown in Figure 3. The volumetric flow rate of air through the main
pipe at circular cross-section (1) is given as Q = 0.0164  m^3/s and the volumetric flow rate of the dye which is
sucked from resorvoir A is given as Q = 0.00082  m^3/s. The air and the dye flow is mixed in the main pipe
and the mixture flow is then sprayed into a material to be dyed at cross-section (3). The pressure at point B
where the sucked dye enters into main pipe is given as 0.95P2 and the diameter of the suction pipe which
connects the reservoir A to the main pipe is D1= 1  cm. Determine the manometric (gauge) pressure of
reservoir A, PA and the density of the mixture flow,  at section (3). The fluids are incompressible and the
friction can be neglected. The pressure at Sections (1) and (3) in the main pipe is assumed to be atmospheric
except Section (2) and any variation of the velocity over the pipe cross section can be neglected.
The diameter of the cross-section (1), D1=10  cm, the diameter of the cross-section (2), D2= 5  cm, the
diameter of the cross-section (3), D3= 10  cm, the dye density, = 800  kg/m^3 and air density, ρair = 1.2  kg/m^3.
The value of gravitational acceleration, g is 9.81 N/kg. (30 Points)

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University Physics with Modern Physics
Hugh D. Young 14th Edition
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Urgent! Expert in fluid mechanics needed Question 3: A dye suction device is arranged as shown in Figure 3. The volumetric flow rate of air through the main pipe at circular cross-section 1 is given as Q = 0.0164 m/s, and the volumetric flow rate of the dye which is sucked from reservoir A is given as Q = 0.00082 m/s. The air and the dye flow are mixed in the main pipe, and the mixture flow is then sprayed into a material to be dyed at cross-section 3. The pressure at point B, where the sucked dye enters into the main pipe, is given as 0.95P, and the diameter of the suction pipe which connects reservoir A to the main pipe is D = 1 cm. Determine the manometric (gauge) pressure of reservoir A, P, and the density of the mixture flow, P, at section 3. The fluids are incompressible, and the friction can be neglected. The pressure at sections 1 and 3 in the main pipe is assumed to be atmospheric, except section 2, and any variation of the velocity over the pipe cross-section can be neglected. The diameter of cross-section 1, D = 10 cm, the diameter of cross-section 2, D = 5 cm, the diameter of cross-section 3, D = 10 cm. The dye density, P = 800 kg/m, and air density, Pair = 1.2 kg/m. The value of gravitational acceleration, g, is 9.81 N/kg. 30 Points
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Transcript

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00:01 Hi guys, now in this flow, if a cross -sectional area of a pipe is 2 meter per second square, 2 meter square, and fluid in it has a speed of 1 .5 meter per second.
00:23 Let's say this is a, we have a pipe.
00:29 Now the cross -sectional area of this one is like this.
00:35 This area is like this.
00:39 A fluid is moving at a speed of what? that is 1 .5 meter per second cross -section area a is equal to 2 so what will be volume flow rate dv divide by d t is equal to a times of v this is i'm going to say that this is this is a volume flow rate that means i need to say that this is capital of v divide by d t this is small of v here we have v is what speed so this is 2 times 1 .5 that means 3 meter cube per second...
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