Use a change of variables or the table to evaluate the following definite integral. \int_{-\frac{\pi}{4}}^{-\frac{\pi}{6}} \frac{-\sin x}{\cos^2 x} dx
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Step 1: We can use the trigonometric identity: \[ \sin^2(x) + \cos^2(x) = 1 \] to rewrite the integrand as: \[ K16 - \sin(x) \cdot \cos(x) = K16 - \frac{1}{2} \sin(2x) \] Show more…
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