Use a Double- or Half-Angle Formula to solve the equation in the interval [0, 2π). (Enter your answers as a comma-separated list.) cos(2θ) + sin2(θ) = 0
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Step 1
First, we can use the double-angle formula for cosine: cos(2θ) = 1 - 2sin^2(θ) Now, substitute this into the given equation: 1 - 2sin^2(θ) + sin^2(θ) = 0 Combine the terms with sin^2(θ): 1 - sin^2(θ) = 0 Now, solve for sin^2(θ): sin^2(θ) = 1 Show more…
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