Question

Q.4. The plate is subjected to the two forces at A and B as shown. If $\theta = 60^\circ$, determine the magnitude of the resultant of these two forces and its direction measured clockwise from the horizontal. $\theta$ A $F_A = 8 \text{ kN}$ $40^\circ$ B $F_B = 6 \text{ kN}$

          Q.4.
The plate is subjected to the two forces at A and B as
shown. If $\theta = 60^\circ$, determine the magnitude of the resultant
of these two forces and its direction measured clockwise
from the horizontal.
$\theta$
A
$F_A = 8 \text{ kN}$
$40^\circ$
B
$F_B = 6 \text{ kN}$

Q.4.
The plate is subjected to the two forces at A and B as
shown. If θ = 60^∘, determine the magnitude of the resultant
of these two forces and its direction measured clockwise
from the horizontal.
θ
A
FA = 8 kN
40^∘
B
FB = 6 kN

Added by Ashley L.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Supreeta N

Step 1

First, let's resolve the forces into their horizontal and vertical components. - Force F at point A: Fx = F * cos(Î¸) = 8 kN * cos(60.9Â°) - Force F at point A: Fy = F * sin(Î¸) = 8 kN * sin(60.9Â°) - Force Fn at point B: Fnx = Fn * cos(Î¸) = 6 kN * Show more…

Show all steps

Thanks for your feedback!

0.4. The plate is subjected to the two forces at A and B as shown. If Î¸ = 60.9Â°, determine the magnitude of the resultant of these two forces and its direction measured clockwise from the horizontal. F = 8 kN 40e Fn = 6 kN