00:01
Hi, i'm david and i'm hitchie.
00:02
Have you answered your question.
00:03
Now let me bring up your question here.
00:06
In the question here, let me summarize the question by the three diagram for you.
00:10
Here we have the y1, y2, y3 form a partition under sambor space s.
00:15
So we have the three partitions, the y1, y2 and the y3, where we have the probability of the y1 equal to the 0 .5, y2 equal to the zipon 2 and for the y3 we tend to the 1 minus 015 minus 7 2 equal to the z1 3 now given that's the y1 we will have either it will be the probability of the x and not x so this is the same thing x not x and not x here we are told that the probability of the x given the y1 equal to the zon 6 so not x will be the common among the zipon 6 equals to 1 minus 6 016 equal to the 014.
01:01
Now probability x given the y2 equal to the 0 .1 1.
01:04
So this one will be the 0111.
01:06
The common 1 will be the 019.
01:08
Probability x given y 3 equal to the 0143.
01:12
This one common will be the 017.
01:14
And that will be the summary in the question...