00:01
Here let's draw a tree diagram.
00:02
It's a bit clearer than base theorem.
00:05
So start off with event b, and we know the outcome for b.
00:11
So b and not b.
00:14
B is 0 .4.
00:17
That's from here.
00:18
That we're told in the question.
00:21
So not be then must be 0 .6, 1 minus 0 .4.
00:26
Remember tree diagrams, the branches add to give you 1.
00:31
Now we're told here that p of a given b is a occurred is 0 .2.
00:36
So here then we have events a and not a and we know here is 0 .2, a given b.
00:46
B has happened, so we're here.
00:49
So a happening is 0 .2, which means here it must be 0 .8.
00:53
Again, 1 minus 0 .2.
00:56
Here we're told p of a given b is not occurred is 0 .9.
01:00
So let's go a branch here.
01:02
A not a.
01:04
Here is 0 .9.
01:06
So here is 0 .1.
01:11
Now, we know that p of a and b in general is equal to p of event a times p of event b, given that a has occurred.
01:28
That you will find on all formula sheets, standard formula.
01:34
I want to work out this one here that i want to find.
01:40
This i can work out, p of a and b, from up here.
01:46
This one is a and b...